const regex = /^(?!.*\/s\/123)(?!.*\/s\/32A )(?!.*atr\/will)([\/a-zA-Z]*)\/_MyWord\/(.*)$/gm;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('^(?!.*\\\/s\\\/123)(?!.*\\\/s\\\/32A )(?!.*atr\\\/will)([\\\/a-zA-Z]*)\\\/_MyWord\\\/(.*)$', 'gm')
const str = `/s/123/QWERERTYU/_MyWord/45454545
atr/will/DFGH/FGHJK/GHJK/_MyWord/DFGHJ452
/DFGH/FGHJK/GHJK/_MyWord/DFGHJ452
HiCanYouHelpMe/_MyWord/fgh
/_MyWord/HiCanYouHelpMefgh
I am handling user input in my program by using regular exp.
the string contains /_MyWord/ and only a-z is accepted before /_MyWord/.
the string not contain /s/123, /s/32A and atr/will in the beginning.
My try:
^(?!.*/s/123)(?!.*/s/32A )(?!.*atr/will)([/a-z]+)/_MyWord/(.*)\$
Example:
/s/123/QWERERTYU/_MyWord/45454545 -> fail
/DFGH/FGHJK/GHJK/_MyWord/DFGHJ452 -> OK
HiCanYouHelpMe/_MyWord/fgh -> OK
/_MyWord/HiCanYouHelpMefgh -> OK`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions