import Foundation
let pattern = #"^(?!.*\/s\/123)(?!.*\/s\/32A )(?!.*atr\/will)([\/a-zA-Z]*)\/_MyWord\/(.*)$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
/s/123/QWERERTYU/_MyWord/45454545
atr/will/DFGH/FGHJK/GHJK/_MyWord/DFGHJ452
/DFGH/FGHJK/GHJK/_MyWord/DFGHJ452
HiCanYouHelpMe/_MyWord/fgh
/_MyWord/HiCanYouHelpMefgh
I am handling user input in my program by using regular exp.
the string contains /_MyWord/ and only a-z is accepted before /_MyWord/.
the string not contain /s/123, /s/32A and atr/will in the beginning.
My try:
^(?!.*/s/123)(?!.*/s/32A )(?!.*atr/will)([/a-z]+)/_MyWord/(.*)$
Example:
/s/123/QWERERTYU/_MyWord/45454545 -> fail
/DFGH/FGHJK/GHJK/_MyWord/DFGHJ452 -> OK
HiCanYouHelpMe/_MyWord/fgh -> OK
/_MyWord/HiCanYouHelpMefgh -> OK
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression