re = /(?<street>[\S ]+?)\s*(?<number>\d+\s*[a-zA-Z]*\s*([-\/]\s*\d*\s*\w?\s*)*)$/m
str = 'Wittenberger Straße 9221
Wittenberger Str. 92
Straße des 17. Juni 122a
Straße des 17 Juni 122a
Str. 545 3
Dr.-Külz-Ring 13
Kanalstraße 13 /1
Prager Str. 3 a
Prager Str. 3a
Prager Str. 3 asd
Erika-Mann-Straße 61 - 61s
Erik-Mann-Straße 61 - 62
Erika-Mann-Straße 61 -62
Erika-Mann-Straße 61b-61c-23d
Erika-Mann-Straße 61b/61c/23d/61b/61c/23d
dsaASa
III. Tongraben5
3. Tongrabe 5
55er Str. 5
%§$§§ 2
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html