re = /^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\s+(?:[03-9]|\d{2,})$/m
str = '# 111.111.111.111
112.112.112.112 1
113.113.113.113 2
114.114.114.114 3
115.115.115.115 4
115.115.115.115 445
115.115.115.115 123'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html