import Foundation
let pattern = #"^((10|127)(\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))|169\.254|192\.168|172\.(2[0-9]|1[6-9]|3[0-1]))(\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)){2}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Private ranges
10.0.0.0-10.255.255.255
127.0.0.0-127.255.255.255
169.254.0.0-169.254.255.255
172.16.0.0-172.31.255.255
192.168.0.0-192.168.255.255
-----OK-----
10.0.0.0
10.255.255.255
127.0.0.0
127.255.255.255
169.254.0.255
169.254.255.255
172.16.0.0
172.31.255.255
192.168.0.0
192.168.255.255
------NOT OK------
1.1.1.1
9.255.255.255
11.0.0.0
126.255.255.255
128.0.0.0
169.253.255.255
169.255.0.0
172.15.255.255
172.32.0.0
192.167.255.255
192.169.0.0
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression