const regex = /\((?:[^()]++|(?R))*\)/gm;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('\\((?:[^()]++|(?R))*\\)', 'gm')
const str = `SELECT Name AS [Object Name], Switch([Type]=5,'Query',[Type]=-32768,'Form',[Type]=6,'Table') AS [Object Type], Switch([Type]=5,1,[Type]=-32768,2,[Type] In (1,4,6),6) AS [Object Type ID], Left(Name,4) as Prefix, LTrim(RTrim(Mid([Name],5,30))) as Suffix
SELECT "Amy's code is righteous.", left("abc",1), right('source code',4), "Bill's code has been righteous too."
----------
End goal is to replace all commas in SQL SELECT clause with comma+linefeed but ignore commas inside parenthesis (which may be nested).
\\((?:[^()]++|(?R))*\\)
This expression will find all of the nested parentheis using recursion. I want to do one of these two options:
a) Replace all commas in the matched groups with the pipe "|" character,
then with two simple StrReplace() calls: replace all commas with comma+linefeed, then replace all | with comma.
OR
b) Select all text that is not in the matched group and replace commas with comma+linefeed.
I'm using AutoHotkey and the RegExReplace() function.`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions