// include the latest version of the regex crate in your Cargo.toml
extern crate regex;
use regex::Regex;
fn main() {
let regex = Regex::new(r"(?m)\((?:[^()]++|(?R))*\)").unwrap();
let string = "SELECT Name AS [Object Name], Switch([Type]=5,'Query',[Type]=-32768,'Form',[Type]=6,'Table') AS [Object Type], Switch([Type]=5,1,[Type]=-32768,2,[Type] In (1,4,6),6) AS [Object Type ID], Left(Name,4) as Prefix, LTrim(RTrim(Mid([Name],5,30))) as Suffix
SELECT \"Amy's code is righteous.\", left(\"abc\",1), right('source code',4), \"Bill's code has been righteous too.\"
----------
End goal is to replace all commas in SQL SELECT clause with comma+linefeed but ignore commas inside parenthesis (which may be nested).
\\((?:[^()]++|(?R))*\\)
This expression will find all of the nested parentheis using recursion. I want to do one of these two options:
a) Replace all commas in the matched groups with the pipe \"|\" character,
then with two simple StrReplace() calls: replace all commas with comma+linefeed, then replace all | with comma.
OR
b) Select all text that is not in the matched group and replace commas with comma+linefeed.
I'm using AutoHotkey and the RegExReplace() function.";
// result will be an iterator over tuples containing the start and end indices for each match in the string
let result = regex.captures_iter(string);
for mat in result {
println!("{:?}", mat);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Rust, please visit: https://docs.rs/regex/latest/regex/