import re
regex = re.compile(r"\((?:[^()]++|(?R))*\)", flags=re.MULTILINE)
test_str = ("SELECT Name AS [Object Name], Switch([Type]=5,'Query',[Type]=-32768,'Form',[Type]=6,'Table') AS [Object Type], Switch([Type]=5,1,[Type]=-32768,2,[Type] In (1,4,6),6) AS [Object Type ID], Left(Name,4) as Prefix, LTrim(RTrim(Mid([Name],5,30))) as Suffix\n\n"
"SELECT \"Amy's code is righteous.\", left(\"abc\",1), right('source code',4), \"Bill's code has been righteous too.\"\n\n"
"----------\n\n"
"End goal is to replace all commas in SQL SELECT clause with comma+linefeed but ignore commas inside parenthesis (which may be nested).\n\n"
"\\((?:[^()]++|(?R))*\\)\n\n"
"This expression will find all of the nested parentheis using recursion. I want to do one of these two options:\n"
" a) Replace all commas in the matched groups with the pipe \"|\" character, \n"
" then with two simple StrReplace() calls: replace all commas with comma+linefeed, then replace all | with comma.\n"
"OR\n"
" b) Select all text that is not in the matched group and replace commas with comma+linefeed.\n\n"
"I'm using AutoHotkey and the RegExReplace() function.")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html