# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"((?<DATE>\d{1,2}\/\d{1,2}\/\d{2})\s[A-Z0-9]{4}\/\d{7}(?<LE>\s[A-Z]{4}\d{6}\-\d).*(?<LPreis>\s\d+,\d{2})\s+06[\s\S]*?(?<GGF>(?=(Dangerous goods:).\d,\d{2})|)(.|\n)*?(?<SUB>(?=(SUBSIDIES)\s+\d+,\d{2})|)(.|\n)*?(?<ADR>(?=(ADR SURCHARGE CH)\s+\d+,\d{2})|).*)"
test_str = ("* 19/11/21 SSS2/3000000 AAAA300007-0 028/2 782 4000 690,00 06\n"
"5527315\n"
"Dangerous goods: 150,00\n"
"Additional performances:\n"
"- SUPPL.REDUCTION CH GOVERNMENT SUBSIDIES 5,00\n"
"- ADR SURCHARGE CH 2,00\n\n"
"19/11/21 BBB2/6000000 BBBB200006-0 222/2 715 2620 690,00 06\n"
"5545628\n"
"Additional performances:\n"
"- SUPPL.REDUCTION CH GOVERNMENT SUBSIDIES 150,00")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html