re = /(?:2019|20[2-9][0-9]|2[1-9][0-9]{2}|[3-9][0-9]{3})/m
str = '3
1000
2000
2018
2019
2020
2021
2100
2800
3001
4001
4000
7044
4444
9999'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html