re = /(0[1-9]|1[0-2])[\/\-](0[1-9]|1[\d]|2[\d]|3[01])[\/\-](\d{2,4})/m
str = '31/12/2019
12/12/2029
12-19-19
19-23-2019
01-23-2018
15-89-2019
02-26-1974
02-50-1978
11/05/19'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html