const regex = new RegExp('(?:\\G(?!\\A)|<img)
(?s:.+?\\bsrc=[\\'"])\\K
https?://.+?(?=/wp-content/)', 'g')
const str = `<img
src="https://www.example.com/de/wp-content/uploads/sites/1/2017/03/image.jpg"
data-srcset="
https://www.example.com/de/wp-content/uploads/sites/1/2017/03/img1.jpg 507w,
https://www.example.com/de/wp-content/uploads/sites/1/2017/03/img2.jpg 780w,
https://www.example.com/de/wp-content/uploads/sites/74/2017/03/img3.jpg 950w"
data-sizes="
(min-width: 80em) calc(0.5 * (100vw - (100vw- 57em))),
(min-width: 48em) calc(0.5 * (100vw - 5em)),
calc(100vw - 1em)"
alt="image" class="lazyload">
<img
src="https://www.example.com/de/wp-content/uploads/sites/1/2017/03/image.jpg"
data-srcset="
https://www.example.com/de/wp-content/uploads/sites/1/2017/03/img1.jpg 507w,
https://www.example.com/de/wp-content/uploads/sites/1/2017/03/img2.jpg 780w,
https://www.example.com/de/wp-content/uploads/sites/74/2017/03/img3.jpg 950w"
data-sizes="
(min-width: 80em) calc(0.5 * (100vw - (100vw- 57em))),
(min-width: 48em) calc(0.5 * (100vw - 5em)),
calc(100vw - 1em)"
alt="image" class="lazyload">`;
const subst = `http://someotherdomain.com`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions