import Foundation
let pattern = #"^((?<leapFeb>(([13579]{1}[26]{1})|([02468]{1}[048]{1}))02(([0]{1}[1-9]{1})|([12]{1}[0-9]{1})))|(?<nonLeapYear>(?<anyYear>[0-9]{2})(?<nonLeapYearMonths>(?<all31DayMonths>([0]{1}[13579]{1}|[1]{1}[02]{1})(([0]{1}[1-9]{1})|([12]{1}[0-9]{1})|[3]{1}[01]{1}))|(?<all30DayMonths>([0]{1}[468]{1}|[1]{1}[1]{1})(([0]{1}[1-9]{1})|([12]{1}[0-9]{1})|[3]{1}[0]{1}))|(?<nonLeapYearFeb>02(([0]{1}[1-9]{1})|([1]{1}[0-9]{1})|([2]{1}[0-8]{1}))))))$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
850228
850229
840229
930822
930922
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression