re = /([äöüÄÖÜßa-zA-Z\-\. ]+)\s*(\d+.*)/m
str = 'Eichetstrasse 21
Meiereistr.28
Dominikus-Schneider-Str. 9
Lindacher-Str.48 d
Langeßallee27
Neuer Weg 68 B
Beuthener Str.9-15'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html