import Foundation
let pattern = #"value\s+(one|two|three)\s+=\s+([0-9]+)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Statistics indicator:0x222235
number of records = 3
records[0]
value one = 2
value two = 5
blocks = 2
block[0] {
some irrelevant data....
value three = 4 bytes
}
block[1]{
some irrelevant data...
value three = 6 bytes
}
records[1]
value one = 3
value two = 5
blocks = 1
block[0] {
some irrelevant data....
value three = 4 bytes
}
records[2]
value one = 7
value two = 6
blocks = 2
block[0] {
some irrelevant data....
value three = 3 bytes
}
block[1]{
some irrelevant data...
value three = 4 bytes
}
Statistics indicator:0x135256
number of records = 2
records[0]
value one = 4
value two = 8
blocks = 1
block[0] {
some irrelevant data....
value three = 6 bytes
}
records[1]
value one = 3
value two = 5
blocks = 1
block[0] {
some irrelevant data....
value three = 3 bytes
}
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression