re = /^Heading +(1).*(?:\r?\n(?! *Heading).*)*?\r?\n.*?SubheadingB: *(.*)/m
str = 'Heading -1
SubheadingB: SomethingBB
SubheadingC: SomethingCC
Heading 0
SubheadingA: SomethingDD
SubheadingB: SomethingEE
SubheadingC: SomethingFF
Heading 1
SubheadingA: SomethingX
SubheadingB: SomethingY
SubheadingC: SomethingZ
Heading 2
SubheadingA: SomethingGG
SubheadingB: SomethingHH
Heading 3
SubheadingA: SomethingJJ
SubheadingB: SomethingKK
SubheadingC: SomethingLL'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html