import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "<loc>(.+)<\\/loc>.*2020-08-06";
final String string = "<?xml version='1.0' encoding='UTF-8'?><urlset xmlns=\"http://www.sitemaps.org/schemas/sitemap/0.9\">\n"
+ "<url><loc>https://google.com/2020/08/this1.html</loc><lastmod>2020-08-06T11:30:55Z</lastmod></url>\n"
+ "<url><loc>https://google.com/2020/08/this2.html</loc><lastmod>2020-08-05T11:30:06Z</lastmod></url>\n"
+ "<url><loc>https://google.com/2020/08/this3.html</loc><lastmod>2020-08-06T11:29:25Z</lastmod></url>\n"
+ "</lastmod></url></urlset>";
final String subst = "\\1";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html