re = /100(\.[0]{1,2})?|([0-9]|[1-9][0-9])(\.[0-9]{1,2})? %/m
str = 'Service Level Report for BESIX CONSTRUCT L.L.C For October 2022 to December 2022 Section 1 - SLA Status DPI Basic Availability Service details Uptime Comments
Description
Service Type Media Option Committed Actual Status 900102711890_DPI - DPI - Main - Besix Basic IDA Fiber/- Basic 99 100.00 % Complied
construct LLC DPI Basic Jitter Service details Uptime Comments
Description
Service Type Media Option Committed Actual Status 900102711890_DPI - DPI - Main - Besix Basic IDA Fiber/- Basic 95 79.44 % Violated
construct LLC DPI Basic Latency Service details Uptime Comments
Description
Service Type Media Option Committed Actual Status 900102711890_DPI - DPI - Main - Besix Basic IDA Fiber/- Basic 95 98.94 % Complied
construct LLC DPI Basic Packet Loss Service details Uptime Comments
Description
Service Type Media Option Committed Actual Status 900102711890_DPI - DPI - Main - Besix Basic IDA Fiber/- Basic 95 99.93 % Complied
construct LLC 24/02/2023 15:07:08 +0400'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html