re = /^(.+)\1$/m
str = 'customer servicescustomer services
House of FraserHouse of Fraser
Managing DirectorManaging Director
Adebanbutayo Trading StoresAdebanbutayo Trading Stores
Jan 2012 - Present · 10 yrs 2 mosJan 2012 - Present · 10 yrs 2 mos'
subst = '\\1'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html