import Foundation
let pattern = #"\A((?:(?!127\.0\.0\.1\s)[\s\S])*?)(?:\Z|127\.0\.0\.1\s+(?!localhost)\S+\n|(127\.0\.1\.1\s+\S+(?![\s\S]*\n127\.0\.0\.1\s)\n))"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
127.0.1.1 myhost
1.1.1.1 bla
127.0.0.1 bla
2.2.2.2 bla
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"\1\2127.0.0.1 localhost\n"#
let lookupRange = (testString as NSString).range(of: pattern, options: .regularExpression, range: stringRange)
if lookupRange.intersection(stringRange) != nil {
let result = regex.stringByReplacingMatches(in: testString, range: lookupRange, withTemplate: substitutionString)
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression