import Foundation
let pattern = #"url(\(((?:[^()]+|(?1))+)\))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = ##"""
url(https://exemples.com/fonts/lato/lato/lato-regular-webfont.ttf)
src:url(https://exemples.com/fonts/lato/lato-regular-webfont.eot?#iefix)
background:url(https://exemples.com/product/header/img.png)
background:url(/product/header/img.png)
background:url("/product/header/img.png")
background:url('/product/header/img.png')
background:url(/uploads/2019/03/0002-image(thumbnail_product).jpg)
.card-thumb__img1{display:block;width:142px;height:62px;background:url(https://example.com/product01.jpg) center center no-repeat;background-size:contain}@media (max-width:1029px).card-thumb__img2{display:block;z-index:1;background:url(https://example.com/product02.jpg) center center no-repeat #000;
background-image: url(/uploads/2019/03/product01-image(thumbnail_photo).jpg);
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression