re = /\d{1,3}(?:\.\d{3})+,\d{2}$/m
str = '1.000.000,00
10.000,00
1.000,00
999.999.999.999.999.999,00
1,567,00
12.45,00
1.456.234.123,00,00'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html