import re
regex = re.compile(r"^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\/((((([0-9])|(?:[1-2][0-9])|(?:3[0-2]))|(([1-9]?\\d|1\\d\\d|25[0-5]|2[0-4]\\d)\.){3}([1-9]?\\d|1\\d\\d|25[0-5]|2[0-4]\\d)(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])))|(((255\.){3}(255|254|252|248|240|224|192|128|0+))|((255\.){2}(255|254|252|248|240|224|192|128|0+)\.0)|((255\.)(255|254|252|248|240|224|192|128|0+)(\.0+){2})|((255|254|252|248|240|224|192|128|0+)(\.0+){3})))$", flags=re.MULTILINE)
test_str = ("0.0.0.0/32\n"
"10.10.10.10/32\n"
"10.10.10.10/255.255.255.255\n"
"99.99.99.99\n"
"100.100.100.100\n"
"199.199.199.199\n"
"200.200.200.200\n"
"255.255.255.255\n"
"255.255.255.255/24\n"
"256.256.256.256\n"
"1.1.1.1.1")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html