re = /^(?![\d.]{18})\d{1,3}(?:\.\d{3})*(?:,\d\d?)?$/m
str = '1.000.000.000.000
1.000.000.000.000,00
1
1,00
123,45
10.000.000.000.000
10.000.000.000.000,00
10.000.000.000.000.000
10.000.000.000.000.000,00'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html