re = /((?<!\d)\d{5}(?!\d))/m
str = '
im having trouble regarding my Regular Expression Pattern:
I need a pattern to extract exact 5 consecutive numeric only
ExampleA: 123456789 dsadss12345@3_- 1d22d333
ExampleB: 12345_ 2d2d2 aaa2222a
ExampleC: 2d2jj ddd_@12345
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html