$re = ';(?s)^.*\s\n^(48\s50\s20\s43\s45\s32\s35\s35\s41\s00|48\s50\s20\s43\s45\s32\s35\s35\s58\s00)$(?=.*:\1=(\w+))$;m';
$str = '42 6C 61 63 6B 20 43 61 72 74 72 69 64 67 65 20
48 50 20 43 45 32 35 35 58 00
Dictionary:48 50 20 43 45 32 35 35 41 00=7000:48 50 20 43 45 32 35 35 58 00=3000
';
$subst = "\2";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php