import Foundation
let pattern = #"(?=\+?\d{1,2}[\s\W]?((?=\(\d{3}\))|(?!\()\d{3}\)?[\s\W]?\d{3}[\s\W]?\d{4}))(?!\+?(?<numberToCheckMask>\d)\k<numberToCheckMask>?.{0,2}\k<numberToCheckMask>{3}.{0,2}\k<numberToCheckMask>{3}.{0,1}\k<numberToCheckMask>{4})(?<phoneNumberToGetDouble>\+?\d{1,2}.{0,2}\d{3}.{0,2}\d{3}.{0,1}\d{4})"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
1 (820)800-8000 \\should match
<h3>4. Recovery Attempt</h3>
<p>Using advanced techniques and proprietary tools, the experts at Rootkit Hacker Firm will attempt to recover your lost Ethereum. Their methods may involve:</p>
<ul>
<li><strong>Brute Force Attack:</strong> Systematically checking all possible passwords until the correct one is found.</li>1 (820)800-8000
999-999-9999 999-999-9999 \\should not match +00-000-000-0000 +00-000-000-0000
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression