import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "(['\"])((?:(?!\\1|\\\\).|\\\\.)*)\\1";
final String string = "Hello Colm \"This is a test\\\\\\\\\"\n"
+ "\"This is also an NL test\"\n"
+ "'And this has an escaped quote don\\'t in it ' Blue Boy\n"
+ "\"This has a single quote ' but doesn\\' end the quote as it started with double quotes\"\n\n"
+ "\"line spanning with escaped quote at the end of a line\\\"\n"
+ "\"\n\n"
+ "\"Foo Bar\" \"Another Value\" something else\n\n"
+ "\"2005014523\",\"34.95661\",\"-96.74025\",\"1\",\"52\",\"52\",\"5/17/2020 - 11:10 AM\",\"By 5/17/2020 2:38 PM\",\"5/17/2020 - 12:50 PM\",\"UNPLANNED\"\n\n"
+ "Empty? \"\" Empty, line spanning \"\n"
+ "\" ";
final String subst = "Subbed";
final Pattern pattern = Pattern.compile(regex, Pattern.DOTALL | Pattern.COMMENTS);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html