re = /^(?:(2)|3)\d{3} \d{4} \d{4} \d{4}(?(1) \d)$/m
str = '2123 1234 1234 1234 5
3123 1234 1234 1234
2234 1234 1234 1234
3234 1234 1234 1234 1'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html