import Foundation
let pattern = #"(\b91|\b0|\b)([6-9]\d{9})\b"#
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = #"""
9207323601
8343434349
6790312345
9739393939
7777598086
my number is 7777598086
7777598086-
91-7777598086
+91-7777598086
+917777598086
+917777598086 is my number
07777598086
+91-07777598086
invalid inputs:
92073236011
47777598086
s77777598086
77777598086s
777777598086
1077777598086
+91077777598086
123149177777598086
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression