re = /^(0?[1-9]|1[012])\/(0?[1-9]|[12]\d|3[01])\/[12]\d{3} ([01]\d|2[0-3])\:[0-5]\d\:[0-5]\d$/
str = '
2/2/2013 00:00:00
2/2/2013 12:30:20'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html