re = /^[+-]?\d+\.\d{1,12}$/m
str = '1.1
0
1.123456789123
a1223
0000.1111
1.abv
0.00
1.0
0.0
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html