re = /((02\/[0-2]\d)|((01|[0][3-9]|[1][0-2])\/(31|30|[0-2]\d)))\/[12]\d{3}/
str = '01/02/2017 #pass
12/31/2017 #pass
02/31/2017
02/12/2017
1/02/2017 #fail
01/2/2017 #fail
50/01/2017 #fail
01/50/2017 #fail'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html