re = /^(?<!\d\. )([A-Z\s]+)/m
str = 'HEADER ONE: Some text within header one.
HEADER TWO: Some text within header two. More lines of text within header two.
1. SUBHEADER INSIDE HEADER TWO: Some text within subheader two.'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html