# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"(?:src=)(\".*?\")"
test_str = "Russia's National Settlement Depository discusses why it believes the biggest blockchain opportunities have yet to be uncovered.<img alt=\"\" height=\"1\" src=\"http://feeds.feedburner.com/~r/CoinDesk/~4/rvoQUj-KDaw\" width=\"1\" />|One of the co-founder of digital currency startup Stellar announced their resignation today.<img alt=\"\" height=\"1\" src=\"http://feeds.feedburner.com/~r/CoinDesk/~4/xRzN7syt-v0\" width=\"1\" />|The editorial board for Bloomberg News has called for a permissive regulatory environment for blockchain development.<img alt=\"\" height=\"1\" src=\"http://feeds.feedburner.com/~r/CoinDesk/~4/ooQYB2iDxP8\" width=\"1\" />"
subst = "\\1"
# You can manually specify the number of replacements by changing the 4th argument
result = re.sub(regex, subst, test_str, 0)
if result:
print (result)
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html