import Foundation
let pattern = #"""
(
\+?
(?:
(?:
9[976]\d
|
8[987530]\d
|
6[987]\d
|
5[90]\d
|
42\d
|
3[875]\d
|
2[98654321]\d
|
9[8543210]
|
8[6421]
|
6[6543210]
|
5[87654321]
|
4[987654310]
|
3[9643210]
|
2[70]
|
7
|
0
|
1
)
|
\(
(?:
9[976]\d
|
8[987530]\d
|
6[987]\d
|
5[90]\d
|
42\d
|
3[875]\d
|
2[98654321]\d
|
9[8543210]
|
8[6421]
|
6[6543210]
|
5[87654321]
|
4[987654310]
|
3[9643210]
|
2[70]
|
7
|
1
)
\))
[0-9. -]{4,14}
)(?:\b|x\d+)
"""#
let regex = try! NSRegularExpression(pattern: pattern, options: .allowCommentsAndWhitespace)
let testString = #"""
+86-400-660-8680
+86-400-660-8680
+1 888 204 3539
1-800-667-6389
+1-400-660-8680
(877) 359-6695
800-692-7753
0365987456
+3342568795
05987213
+33 321 82
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression