re = /(([0-1]{8})([0-1]{24}))/m
str = '010011011001110111100111011010001001100011101100100011100010100011110010100011001111111101101001
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html