re = /\b(?:[1-2]?[0-9]\.[0-9]{1,4})\b[^a-zA-Z\d]{0,3}%?/m
str = '11111
11111.
11111.1111
.11111
a111.1111
99
010
101
100
100.01
2.95%
19.5113%
5.32
0.0250
9.32
24.32
0.0023
30.20
29.23
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html