re = /^(?:(?=(\d)..\1(?!0*$)|(?:0..1|1..2|2..3|3..4|4..5|5..6|6..7|7..8|8..9|9..0)0*$)\d){3}\d{3}$/m
str = 'Pass:
000001
009010
010011
019020
057058
099100
100101
299300
398399
404405
500501
665666
666667
899900
998999
Edge Case:
999000
Not Pass:
000000
123456
123234
000002
010002
010012
050060
397399
0071072
89090
0890900
1234
200210
123123124'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html