re = /^(.*?)((0|1)?\d)-((0|1|2|3)?\d)-(19|20\d\d)(.*?)$/m
str = 'asasa12-12-1993.txt
asassa12-12-2010.txt
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html