re = /(mul)\((\d+),(\d+)\)|(do)\(\)|(don't)\(\)/m
str = 'xmul(2,4)&mul[3,7]!^don\'t()_mul(5,5)+mul(32,64](mul(11,8)undo()?mul(8,5))'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html