import Foundation
let pattern = #"""
[+]?(?<!\d)(?<!\d[ -])
(?:
((\d{1,2}[ -]?)?[(]?\d{3}[)]?[ -]?)
(\d(?:[ -]?\d){3,6})
)(?![ -]?\d)
"""#
let regex = try! NSRegularExpression(pattern: pattern, options: .allowCommentsAndWhitespace)
let testString = #"""
Matches:
--------
1234567 123 45 67 123-45-67
123456789012 12 345 678 9012 12-345-678-90-12
1 234 56 78 912 1 234 56 789 12 1 234 567 8 901
+1234567
+1234567890 +12-234 561 78 90 +12 234-561-78-90
+123456789012
+1 234 561 78 90
1(234)567-89-01
(495)1234567 (495) 123 45 67
+33 (014)-020 53 17
Doesn't match:
--------------
+123456 -- to short
+1234567890123 -- too long
123 4567890123 -- too long
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression