import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = #"(?i)<\/?\w+[^>]*>(*SKIP)(?!)|\b(\p{Latin})\s"#
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = #"""
Dziedziczenie dlugów spadkowych jest wciąż bardzo żywym tematem, pomimo korzystnej dla spadkobierców zmiany przepisów w 2015 roku, o ē której szerzej pisałem na blogu <a href="http://www.prawnik-katowice.pl/blog-prawniczy/dziedziczenie-dlugow-od-18-pazdziernika-2015-roku/">tutaj</a>.
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"\1 "#
let result = regex.stringByReplacingMatches(in: testString, range: stringRange, withTemplate: substitutionString)
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression