import Foundation
let pattern = #"\B%[a-z0-9]+\b"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
1. %xxxxxxxxxxxxx //match
2. this will work %xxxxxx but not this%xxxxxxxxx. //match 1st, not 2nd
3. and also %xxxxxxxxxx. //match
4. just a line ending with %xxxxxxxxxxx //match
5. %Xxxxxxxxxxx //no match
6. 100% of dogs //no match
7. 65%. Begining of new phrase //no match
8. 65%.Begining of new phrase //no match
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression