re = /(.),(.)/m
str = 'SELECT
di.QuestionSetID AS SectionID,
,di.ScoreNBR AS Section,LowestTopBoxNBR
,di.AveragePercentileNBR AS SectionTopBoxPercentileRankNBR
,qdate.Quarter,StartDTS AS Section,StartDTS
FROM NRCPicker.PatientSatisfaction.DimensionPercentile AS di
INNER JOIN (
asdf,,asdf,
,ll
,,,,,,
,,'
subst = '$1 $2'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html