re = /(\d){3}\.?\1{3}\.?\1{3}-?\1{2}/m
str = '000.000.000-00
111.111.111-11
222.222.222-22
333.333.333-33
444.444.444-44
555.555.555-55
666.666.666-66
777.777.777-77
888.888.888-88
999.999.999-99
00000000000
11111111111
22222222222
33333333333
44444444444
55555555555
66666666666
77777777777
88888888888
99999999999
99999999999'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html