import Foundation
let pattern = #"(\d){3}\.?\1{3}\.?\1{3}-?\1{2}"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
000.000.000-00
111.111.111-11
222.222.222-22
333.333.333-33
444.444.444-44
555.555.555-55
666.666.666-66
777.777.777-77
888.888.888-88
999.999.999-99
00000000000
11111111111
22222222222
33333333333
44444444444
55555555555
66666666666
77777777777
88888888888
99999999999
99999999999
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression