import Foundation
let pattern = ##"\[link=https?:\/\/(www\.)?([\da-z\.-]+)\.([a-z\.]{2,6})([\/\w \.-](\S*[&|#]\S+)*)*\/?\][^\s\\](.*?)\[\/link\]"##
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = ##"""
// Lolos
[link=https://namablog.com/]teks[/link]
[link=http://namablog.co.id/]teks[/link]
[link=http://namablog.com/2016/04/vita-denique-conferta-voluptatum-omnium.html]teks[/link]
[link=https://namablog.blogspot.com/2016/04/vita-denique-conferta-voluptatum-omnium.html?showComment=1468398368234#c4159204139756303657]teks[/link]
[link=https://namablog.blogspot.co.id/search?updated-max=2016-04-17T04:28:00-07:00&max-results=7/]teks[/link]
// Tidak lolos
[link=//namablog.com/]teks[/link]
[link=https://namablog.com][/link]
[link=https://namablog.com/]teks[/link
[link=https://namablog]teks[link]
[link=https://namablog.com/]teks/link]
[link=https://namablog.com/]teks[link]
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression