// include the latest version of the regex crate in your Cargo.toml
extern crate regex;
use regex::Regex;
fn main() {
let regex = Regex::new(r"(?i)(\w{2}).*?(\1)").unwrap();
let string = "This is a repeated repeated word.zz zz zz
How would you find pairs of letters that occur twice in a string using regex with Python?
I want to iterate through a list of strings, find the ones that have repeating pairs of letters, and put them into a list. The letters don't need to be the same, the pair just has to repeat, though the letters can be the same.
Ex:
this one has xx twice so I want to keep this string:
xxhgfhdeifhjfrikfoixx
this one would be kept as well, because hd is repeated:
kwofhdbugktrkdidhdnbk
The best I got was to find the pairs: ([a-z][a-z])\\1|([a-z])\\2
I need to find which pairs repeat in the string.";
// result will be an iterator over tuples containing the start and end indices for each match in the string
let result = regex.captures_iter(string);
for mat in result {
println!("{:?}", mat);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Rust, please visit: https://docs.rs/regex/latest/regex/