re = /^(?:09\d{8}|01\d{9}|\d{9})$/m
str = '99819123
998191234
9981912345
01222222222
0933333333
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html